Make a POST with application/x-www-form-urlencoded payload [Solved]

[Number8]

Hello,
I have to send a POST with an application/x-www-form-urlencoded payload. I'm wondering what the syntax should be?
Current script is:

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dz.openURL({
        url = url,
	method = "POST",
        callback = "return",
        postData = {
          turn = "toggle"
        }
})

Thank you

[waaren]

I have to send a POST with an application/x-www-form-urlencoded payload. I'm wondering what the syntax should be?

Something like this ?

Code: Select all

dz.openURL({
                url = url,
                method = 'POST',
                headers = { ['content-Type'] = 'application/x-www-form-urlencoded' },
                postData = { ['turn'] = 'toggle' },
                callback = 'return',
            })

[Number8]

Thanks waaren
Unfortunately it does not work, I don't know why. Strange the API does not return any error.
Using GET however works

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'IPAddress/relay/0?turn=toggle'

[Number8]

Using this curl command works

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curl -X POST -d "turn=toggle"  http://IPaddress/relay/0

What would be then dzVents syntax?

[Number8]

The correct syntax is

Code: Select all

dz.openURL({
        url = url,
	method = 'POST',
        postData = { turn = 'on' },
        callback = 'return'
	})