lua script if Humidity >...% then

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robingerritsen
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lua script if Humidity >...% then

Post by robingerritsen »

Hello,

I'm trying to create a script, that the fan turn on when the humidity above 60% is.
I know that this script is completely wrong but I had something like this in mind:

Code: Select all

commandArray = {}
sWeatherTemp, sWeatherHumidity, sWeatherUV, sWeatherPressure, sWeatherUV2 = otherdevices_svalues[Badkamer]:match("([^;]+);([^;]+);([^;]+);([^;]+);([^;]+)")

sWeatherHumidity = tonumber(sWeatherHumidity);



if (devicechanged['Badkamer'] > 60) then

commandArray['Fan']='On'
   
end
return commandArray



I know that there are many examples, but this would not succeed me
I hope someone can help me
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jvdz
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Re: lua script if Humidity >...% then

Post by jvdz »

Are you sure the device Badkamer contains all that weather data? What is the exact value of the device listed under Setup/Devices?
I guess it should be something like this and name the script script_time_xxxxxx.lua to do the check one time each minute:

Code: Select all

commandArray = {}
sWeatherTemp, sWeatherHumidity, sWeatherUV, sWeatherPressure, sWeatherUV2 = otherdevices_svalues[Badkamer]:match("([^;]+);([^;]+);([^;]+);([^;]+);([^;]+)")
sWeatherHumidity = tonumber(sWeatherHumidity);
if (sWeatherHumidity > 60 and otherdevices['Fan'] == 'Off') then
	print("luchtvochtigheid in de Badkamer is groter dan 60%, zet ventilator aan. " .. sWeatherHumidity)
	commandArray['Fan']='On'
elsif (sWeatherHumidity < 55 and otherdevices['Fan'] == 'On') then
	print("luchtvochtigheid in de Badkamer is lager dan 55%, zet ventilator uit. " .. sWeatherHumidity)
	commandArray['Fan']='Off'
end
return commandArray
EDIT: Updated the script to avoid setting the FAN each minute.
Jos
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robingerritsen
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Re: lua script if Humidity >...% then

Post by robingerritsen »

jvdz wrote:Are you sure the device Badkamer contains all that weather data? What is the exact value of the device listed under Setup/Devices?
I guess it should be something like this and name the script script_time_xxxxxx.lua to do the check one time each minute:

Code: Select all

commandArray = {}
sWeatherTemp, sWeatherHumidity, sWeatherUV, sWeatherPressure, sWeatherUV2 = otherdevices_svalues[Badkamer]:match("([^;]+);([^;]+);([^;]+);([^;]+);([^;]+)")
sWeatherHumidity = tonumber(sWeatherHumidity);
if (sWeatherHumidity > 60 and otherdevices['Fan'] == 'Off') then
	print("luchtvochtigheid in de Badkamer is groter dan 60%, zet ventilator aan. " .. sWeatherHumidity)
	commandArray['Fan']='On'
elsif (sWeatherHumidity < 55 and otherdevices['Fan'] == 'On') then
	print("luchtvochtigheid in de Badkamer is lager dan 55%, zet ventilator uit. " .. sWeatherHumidity)
	commandArray['Fan']='Off'
end
return commandArray
EDIT: Updated the script to avoid setting the FAN each minute.
Jos
Thanks for your reply
I added the script but I get the following error
2016-01-03 13:47:00.094 Error: EventSystem: /home/pi/domoticz/scripts/lua/script_time_Badkamer.lua:7: unexpected symbol near 'then'

I've here a screenshot of the Device page
Screenshot device
Screenshot device
badkamer.png (2.01 KiB) Viewed 4895 times
thankyou
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jvdz
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Re: lua script if Humidity >...% then

Post by jvdz »

I see I had a typo in there for elseif.
Had a closer look at the LUA event options for that type of device and think something like this should work as a "script_device_xxxx.lua" event:

Code: Select all

commandArray = {}
if (devicechanged['Badkamer_Humidity'] > 60 and otherdevices['Fan'] == 'Off') then
	print("luchtvochtigheid in de Badkamer is groter dan 60%, zet ventilator aan. " .. devicechanged['Badkamer_Humidity'])
	commandArray['Fan']='On'
elseif (devicechanged['Badkamer_Humidity'] < 55 and otherdevices['Fan'] == 'On') then
	print("luchtvochtigheid in de Badkamer is lager dan 55%, zet ventilator uit. " .. devicechanged['Badkamer_Humidity'])
	commandArray['Fan']='Off'
end
return commandArray
Wiki refference https://www.domoticz.com/wiki/Events somewhere in the middle of that page.

Jos
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Re: lua script if Humidity >...% then

Post by bizziebis »

I use this Lua script: https://www.domoticz.com/wiki/Humidity_control

Easy to adjust and working very well!
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Re: lua script if Humidity >...% then

Post by robingerritsen »

jvdz wrote:I see I had a typo in there for elseif.
Had a closer look at the LUA event options for that type of device and think something like this should work as a "script_device_xxxx.lua" event:

Code: Select all

commandArray = {}
if (devicechanged['Badkamer_Humidity'] > 60 and otherdevices['Fan'] == 'Off') then
	print("luchtvochtigheid in de Badkamer is groter dan 60%, zet ventilator aan. " .. devicechanged['Badkamer_Humidity'])
	commandArray['Fan']='On'
elseif (devicechanged['Badkamer_Humidity'] < 55 and otherdevices['Fan'] == 'On') then
	print("luchtvochtigheid in de Badkamer is lager dan 55%, zet ventilator uit. " .. devicechanged['Badkamer_Humidity'])
	commandArray['Fan']='Off'
end
return commandArray
Wiki refference https://www.domoticz.com/wiki/Events somewhere in the middle of that page.

Jos
Hi Jos,

Thanks!
I still get an error message, but I think we're almost there

the error message is:
2016-01-03 14:11:00.130 Error: EventSystem: /home/pi/domoticz/scripts/lua/script_device_Badkamer.lua:2: attempt to index field '?' (a nil value)
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Re: lua script if Humidity >...% then

Post by jvdz »

Is the devicename for your Fan correct ('Fan') ? It is case sensitive and need to be the exact name as listed in the Devices overview.

Jos
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Re: lua script if Humidity >...% then

Post by robingerritsen »

jvdz wrote:Is the devicename for your Fan correct ('Fan') ? It is case sensitive and need to be the exact name as listed in the Devices overview.

Jos
yes, it is exactly 'Fan' also with a capital.
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Re: lua script if Humidity >...% then

Post by jvdz »

Have done some proper testing this time with devices I have and this logic worked for me.
It will print a log file entry each time an update is received which you might want to comment out when things are working:

Code: Select all

commandArray = {}
if devicechanged['Badkamer_Humidity'] ~= nil then
	print("luchtvochtigheid in de Badkamer update: " .. devicechanged['Badkamer_Humidity'] .. " Fan:" .. otherdevices['Fan'])
	if (devicechanged['Badkamer_Humidity'] > 60 and otherdevices['Fan'] == 'Off') then
		print("luchtvochtigheid in de Badkamer is groter dan 60%, zet ventilator aan. ")
		commandArray['Fan']='On'
	elseif (devicechanged['Badkamer_Humidity'] < 55 and otherdevices['Fan'] == 'On') then
		print("luchtvochtigheid in de Badkamer is lager dan 55%, zet ventilator uit. ")
		commandArray['Fan']='Off'
	end
end
return commandArray
Jos
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robingerritsen
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Re: lua script if Humidity >...% then

Post by robingerritsen »

sorry there was something wrong with the upload of the script. I have now uploaded the correct script and get the following error message:

2016-01-03 14:36:36.166 Error: EventSystem: /home/pi/domoticz/scripts/lua/script_device_Badkamer.lua:2: attempt to compare number with nil
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jvdz
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Re: lua script if Humidity >...% then

Post by jvdz »

This is for the last script I posted 3 minutes before your last post?

Jos
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Re: lua script if Humidity >...% then

Post by robingerritsen »

jvdz wrote:This is for the last script I posted 3 minutes before your last post?

Jos
Jos you are a hero!! It works!
thank you very much for the time and effort!!
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jvdz
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Re: lua script if Humidity >...% then

Post by jvdz »

robingerritsen wrote: Jos you are a hero!! It works!
thank you very much for the time and effort!!
No worries, it is fun and a learning experience for me too discovering all possibilities with LUA. :)
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Re: lua script if Humidity >...% then

Post by dannybloe »

robingerritsen wrote:Hello,

I'm trying to create a script, that the fan turn on when the humidity above 60% is.
I know that this script is completely wrong but I had something like this in mind:

Code: Select all

commandArray = {}
sWeatherTemp, sWeatherHumidity, sWeatherUV, sWeatherPressure, sWeatherUV2 = otherdevices_svalues[Badkamer]:match("([^;]+);([^;]+);([^;]+);([^;]+);([^;]+)")

sWeatherHumidity = tonumber(sWeatherHumidity);



if (devicechanged['Badkamer'] > 60) then

commandArray['Fan']='On'
   
end
return commandArray



I know that there are many examples, but this would not succeed me
I hope someone can help me
I think that such a script won't do you any good on the long run. The thing is that this 60% threshold varies from day to day. A while ago I had a hygrostat that was supposed to switch on the fan when a certain amount of humidity was registered in the bathroom but I ended up adjusting this threshold almost every day. On a rainy day it was different than on a cold winter's day. I ditched the hygrostat and created the script https://www.domoticz.com/wiki/Humidity_control. That registers a relative rise in humidity level and tries to dehumidify to the level just before the rise. Works like a charm. But you need a humidity sensor of course.
Creator dzVents - RPi3, loads of zwave devices, esp8266, evohome.
robingerritsen
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Re: lua script if Humidity >...% then

Post by robingerritsen »

dannybloe wrote:I think that such a script won't do you any good on the long run. The thing is that this 60% threshold varies from day to day. A while ago I had a hygrostat that was supposed to switch on the fan when a certain amount of humidity was registered in the bathroom but I ended up adjusting this threshold almost every day. On a rainy day it was different than on a cold winter's day. I ditched the hygrostat and created the script https://www.domoticz.com/wiki/Humidity_control. That registers a relative rise in humidity level and tries to dehumidify to the level just before the rise. Works like a charm. But you need a humidity sensor of course.
hello,

I have edit my script. If the humidity is above 65%, the fan wil turn on for 10 minutes. The script does this once per hour

Code: Select all

t1 = os.time()
s = otherdevices_lastupdate['Fan']

 
year = string.sub(s, 1, 4)
month = string.sub(s, 6, 7)
day = string.sub(s, 9, 10)
hour = string.sub(s, 12, 13)
minutes = string.sub(s, 15, 16)
seconds = string.sub(s, 18, 19)


commandArray = {}

t2 = os.time{year=year, month=month, day=day, hour=hour, min=minutes, sec=seconds}
difference = (os.difftime (t1, t2))

if devicechanged['Badkamer_Humidity'] ~= nil then
   print("luchtvochtigheid in de Badkamer update: " .. devicechanged['Badkamer_Humidity'] .. " Fan:" .. otherdevices['Fan'])
   if (devicechanged['Badkamer_Humidity'] >= 65) then
   if (otherdevices['Fan'] == 'Off' and difference > 3600 and difference < 3660) then
      print("luchtvochtigheid in de Badkamer is groter dan 65%, zet ventilator aan. ")
      commandArray['Fan']='On FOR 10'
   end
   end
end
return commandArray
But thanks for your replay, I'm going to see how the Humidity control script works and maybe I'm going to use that script
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jvdz
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Re: lua script if Humidity >...% then

Post by jvdz »

Maybe I am confused now but the result of your test is that the FAN will only be activated when the Humidity is higher than 65% before 1 hour is passed since the last time the fan was activated? When the humidity is only > 65% after the 3660 seconds is passed, the fan will not be activated anymore.

Code: Select all

   if (otherdevices['Fan'] == 'Off' and difference > 3600 and difference < 3660) then
Shouldn't that be that you want to wait at least 1 hour since last activation? like:

Code: Select all

   if (otherdevices['Fan'] == 'Off' and difference > 3600) then
Disadvantage will be when taking a shower, it can take up to 60 minutes before the fan is activated. :)

Jos
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Re: lua script if Humidity >...% then

Post by robingerritsen »

jvdz wrote:Maybe I am confused now but the result of your test is that the FAN will only be activated when the Humidity is higher than 65% before 1 hour is passed since the last time the fan was activated? When the humidity is only > 65% after the 3660 seconds is passed, the fan will not be activated anymore.

Code: Select all

   if (otherdevices['Fan'] == 'Off' and difference > 3600 and difference < 3660) then
Shouldn't that be that you want to wait at least 1 hour since last activation? like:

Code: Select all

   if (otherdevices['Fan'] == 'Off' and difference > 3600) then
Disadvantage will be when taking a shower, it can take up to 60 minutes before the fan is activated. :)

Jos
Thanks Jos!, I have changed my script
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